Giải các phương trình :
$\begin{array}{l}
1)\,\,\,{4^{{{\log }_9}x}} - {6.2^{{{\log }_9}x}} + {2^{{{\log }_3}27}} = 0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)\\
2)\,\,{4^{{{\log }_3}x}} - {5.2^{{{\log }_3}x}} + {2^{{{\log }_3}9}} = 0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(2)
\end{array}$
Đăng bài 24-04-12 01:54 PM
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Đăng bài 24-04-12 01:52 PM
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Đăng bài 24-04-12 01:49 PM
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Đăng bài 24-04-12 01:47 PM
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Đăng bài 24-04-12 01:45 PM
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Giải các phương trình :
$\begin{array}{l}
1)\,\,{3^{x - 5}} = 4\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,3)\,{9^x} - {2^{x + \frac{3}{2}}} = {2^{x + \frac{1}{2}}} - {3^{2x - 1}}\\
2)\,\,{3^{4 - 2x}} = {9^{5 - 3x - {x^2}}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,4)\,{7^{3x}} + {9.5^{2x}} = {5^{2x}} + {9.7^{3x}}
\end{array}$
Đăng bài 24-04-12 01:43 PM
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Giải các phương trình :
$\begin{array}{l}
1)\,\,{2^{x + 2}}{.5^{x + 2}} = {2^{3x}}{.5^{3x}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,3)\,\,{3^{2x + 3}}{.5^{2x + 3}} = {3^{5x}}{.5^{5x}}\\
2)\,\,{3^{x + 3}}{.7^{x + 3}} = {3^{2x}}{.7^{2x}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, 4)\,{2^{x + 4}}{.7^{x + 4}} = {2^{3x}}{.7^{3x}}
\end{array}$
Đăng bài 24-04-12 11:58 AM
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Giải các phương trình :
$\begin{array}{l}
1)\,{\left[ {{{\left( {{2^{\sqrt x + 5}}} \right)}^{\frac{1}{{5\sqrt x + 1}}}}} \right]^{\frac{1}{{\sqrt x }}}} = \frac{1}{2}{.4^{\sqrt x }}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)\\
2)\,\,{2^{{{\log }_8}\left( {{x^2} - 6x + 9} \right)}} = {3^{2{{\log }_x}\sqrt x - 1}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(2)
\end{array}$
Đăng bài 24-04-12 11:55 AM
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Giải các phương trình :
$\begin{array}{l}
1)\,\,{3^{2 + x}} + {3^{2 - x}} = 30\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,3)\,\,{25^x} - {23.5^x} - 5 = 0\\
2)\,{4^x} + {3.2^x} - 10 = 0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,4)\,\,{3^{2\left( {x + 1} \right)}} - {82.3^x} + 9 = 0
\end{array}$
Đăng bài 24-04-12 11:48 AM
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Giải các phương trình :
$\begin{array}{l}
1){2^x} = 128\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, 4)\,{25^x} - {6.5^{x + 1}} + {5^3} = 0\\
2){3^{x - 1}} = \frac{1}{{729}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,5)\,{9^x} + {5.3^x} + 7 = 0\,\\
3){4^x} + {2^x} - 6 = 0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,6)\,{9^x} - {25.3^x} - 54 = 0
\end{array}$
Đăng bài 24-04-12 11:45 AM
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Đăng bài 24-04-12 11:35 AM
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Đăng bài 24-04-12 11:34 AM
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Đăng bài 24-04-12 11:32 AM
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Đăng bài 24-04-12 11:10 AM
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Đăng bài 24-04-12 11:00 AM
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