Đăng bài 24-04-12 11:32 AM
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Đăng bài 25-04-12 08:43 AM
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Đăng bài 02-05-12 11:53 AM
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Đăng bài 12-05-12 08:48 AM
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Giải các phương trình : $\begin{array}{l} 1)\,{\left[ {{{\left( {{2^{\sqrt x + 5}}} \right)}^{\frac{1}{{5\sqrt x + 1}}}}} \right]^{\frac{1}{{\sqrt x }}}} = \frac{1}{2}{.4^{\sqrt x }}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \,\,\,\,\,\,\,\,\,\,(1)\\ 2)\,\,{2^{{{\log }_8}\left( {{x^2} - 6x + 9} \right)}} = {3^{2{{\log }_x}\sqrt x - 1}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\ ,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(2)\end{array}$
Đăng bài 04-05-12 11:07 AM
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Giải các phương trình : $\begin{array}{l} 1)\,{\left[ {{{\left( {{2^{\sqrt x + 5}}} \right)}^{\frac{1}{{5\sqrt x + 1}}}}} \right]^{\frac{1}{{\sqrt x }}}} = \frac{1}{2}{.4^{\sqrt x }}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)\\ 2)\,\,{2^{{{\log }_8}\left( {{x^2} - 6x + 9} \right)}} = {3^{2{{\log }_x}\sqrt x - 1}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(2) \end{array}$
Đăng bài 24-04-12 11:55 AM
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Đăng bài 27-04-12 08:17 AM
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Đăng bài 23-04-12 04:55 PM
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Giải các phương trình sau đây: $\begin{array}{l} 1)\,\,{3^x} + {4^x} = {5^x}\,\,\,\,\,\,\,\,(1)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,4)\,\,\,{3^x} + {4^x} + {5^x}\, = {10^x}\,\,\,\,\,\,\,\,\,\,\,\,(4)\\ 2)\,{2^x} + {3^x} = {5^x}\,\,\,\,\,\,\,\,(2)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,5)\,\,\,\lg \left( {x - 4} \right) = 5 - x\,\,\,\,\,\,\,\,\,\,\,\,\,\,(5)\\ 3)\,{5^x} + {12^x} = {13^x}\,\,\,\,(3) \end{array}$
Đăng bài 08-05-12 02:07 PM
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