Giải phương trình : ${2^{x + 1}} - {4^x} = x - 1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)$
Đăng bài 26-04-12 03:20 PM
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Mỗi phương trình sau đây có bao nhiêu nghiệm : $\begin{array}{l} 1)\,\,{\left( {\frac{1}{3}} \right)^x} = 2x + 1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,3)\,{4^x} = x - 2\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(3)\\ 2)\,{3^x} = x + 5\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(2) \end{array}$
Đăng bài 26-04-12 03:16 PM
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Đăng bài 26-04-12 03:14 PM
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Giải các phương trình sau đây : $\begin{array}{l} 1)\,\,{3^x} + {4^x} = {5^x}\,\,\,\,\,\,\,\,(1)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,4)\,\,\,{3^x} + {4^x} + {5^x}\, = {10^x}\,\,\,\,\,\,\,\,\,\,\,\,(4)\\ 2)\,{2^x} + {3^x} = {5^x}\,\,\,\,\,\,\,\,(2)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,5)\,\,\,\log \left( {x - 4} \right) = 5 - x\,\,\,\,\,\,\,\,\,\,\,\,\,\,(5)\\ 3)\,{5^x} + {12^x} = {13^x}\,\,\,\,(3) \end{array}$
Đăng bài 26-04-12 03:03 PM
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