Ta có:
$\int\limits_0^2|x^2-x|dx$
$=\int\limits_0^1(x-x^2)dx+\int\limits_1^2(x^2-x)dx$
$=\left(\dfrac{x^2}{2}-\dfrac{x^3}{3}\right)\left|\begin{array}{l}1\\0\end{array}\right.+\left(\dfrac{x^3}{3}-\dfrac{x^2}{2}\right)\left|\begin{array}{l}2\\1\end{array}\right.=1$