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sửa đổi
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phương trinh toán 8 siêu khó
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phương trinh toán 8 siêu khó Bài 1:Cho x = \frac {pan style="font-size:11.0pt;line-height:115%;
font-family:"Calibri","sans-serif";mso-ascii-theme-font:minor-latin;mso-fareast-font-family:
Calibri;mso-fareast-theme-font:minor-latin;mso-hansi-theme-font:minor-latin;
mso-bidi-font-family:"Times New Roman";mso-bidi-theme-font:minor-bidi;
mso-ansi-language:EN-US;mso-fareast-language:EN-US;mso-bidi-language:AR-SA">b^2+c^2‐a^2}{pan style="font-size:11.0pt;line-height:115%;
font-family:"Calibri","sans-serif";mso-ascii-theme-font:minor-latin;mso-fareast-font-family:
Calibri;mso-fareast-theme-font:minor-latin;mso-hansi-theme-font:minor-latin;
mso-bidi-font-family:"Times New Roman";mso-bidi-theme-font:minor-bidi;
mso-ansi-language:EN-US;mso-fareast-language:EN-US;mso-bidi-language:AR-SA">2bc} ; y = \frac{pan style="font-size:11.0pt;line-height:115%;
font-family:"Calibri","sans-serif";mso-ascii-theme-font:minor-latin;mso-fareast-font-family:
Calibri;mso-fareast-theme-font:minor-latin;mso-hansi-theme-font:minor-latin;
mso-bidi-font-family:"Times New Roman";mso-bidi-theme-font:minor-bidi;
mso-ansi-language:EN-US;mso-fareast-language:EN-US;mso-bidi-language:AR-SA">a^2‐\leftan style="font-size:11.0pt;line-height:115%;font-family:"Arial","sans-serif";
mso-fareast-font-family:Calibri;mso-fareast-theme-font:minor-latin;mso-ansi-language:
EN-US;mso-fareast-language:EN-US;mso-bidi-language:AR-SA">﴾b‐c\rightn style="font-size:11.0pt;
line-height:115%;font-family:"Arial","sans-serif";mso-fareast-font-family:Calibri;
mso-fareast-theme-font:minor-latin;mso-ansi-language:EN-US;mso-fareast-language:
EN-US;mso-bidi-language:AR-SA">﴿ style="font-size:11.0pt;
line-height:115%;font-family:"Calibri","sans-serif";mso-ascii-theme-font:minor-latin;
mso-fareast-font-family:Calibri;mso-fareast-theme-font:minor-latin;mso-hansi-theme-font:
minor-latin;mso-bidi-font-family:"Times New Roman";mso-bidi-theme-font:minor-bidi;
mso-ansi-language:EN-US;mso-fareast-language:EN-US;mso-bidi-language:AR-SA">^2}{<span style="font-size:11.0pt;line-height:115%;
font-family:"Calibri","sans-serif";mso-ascii-theme-font:minor-latin;mso-fareast-font-family:
Calibri;mso-fareast-theme-font:minor-latin;mso-hansi-theme-font:minor-latin;
mso-bidi-font-family:"Times New Roman";mso-bidi-theme-font:minor-bidi;
mso-ansi-language:EN-US;mso-fareast-language:EN-US;mso-bidi-language:AR-SA">\lefttyle="font-size:11.0pt;line-height:115%;font-family:"Arial","sans-serif";
mso-fareast-font-family:Calibri;mso-fareast-theme-font:minor-latin;mso-ansi-language:
EN-US;mso-fareast-language:EN-US;mso-bidi-language:AR-SA">﴾pan style="font-size:11.0pt;line-height:115%;font-family:"Calibri","sans-serif";
mso-ascii-theme-font:minor-latin;mso-fareast-font-family:Calibri;mso-fareast-theme-font:
minor-latin;mso-hansi-theme-font:minor-latin;mso-bidi-font-family:"Times New Roman";
mso-bidi-theme-font:minor-bidi;mso-ansi-language:EN-US;mso-fareast-language:
EN-US;mso-bidi-language:AR-SA">b+c\right style="font-size:11.0pt;
line-height:115%;font-family:"Arial","sans-serif";mso-fareast-font-family:Calibri;
mso-fareast-theme-font:minor-latin;mso-ansi-language:EN-US;mso-fareast-language:
EN-US;mso-bidi-language:AR-SA">﴿<span style="font-size:11.0pt;
line-height:115%;font-family:"Calibri","sans-serif";mso-ascii-theme-font:minor-latin;
mso-fareast-font-family:Calibri;mso-fareast-theme-font:minor-latin;mso-hansi-theme-font:
minor-latin;mso-bidi-font-family:"Times New Roman";mso-bidi-theme-font:minor-bidi;
mso-ansi-language:EN-US;mso-fareast-language:EN-US;mso-bidi-language:AR-SA">^2‐a^2} Tính giá trị P = x + y + xy Bài 2:
Giải phương trình:
a, \frac{1}{a+b-x} = \frac{1}{a}+\frac{1}{b}+\frac{1}{x} ﴾x là ẩn số﴿ b, \frac{\left﴾b‐c\right﴿\left﴾1+a\right﴿^2}{x+a^2}+\frac{\left﴾c‐a\right﴿\left﴾1+b\right﴿^2}{x+b^2}+\frac{\left﴾a‐b\right﴿\left﴾1+c\right﴿^2}{x+c^2} = 0
﴾a,b,c là hằng số và đôi một khác nhau﴿
phương trinh toán 8 siêu khó Bài 1: Cho x = b2+c2‐a 22bc " role="p resenta tion " style=" display: in li ne -block; line-height: 0; font- si ze: 16.38px; word-wrap: normal; wo rd-s pa cin g: nor mal; whit e-s pace: no wr ap; fl oat : non e; dire ct ion: l tr; ma x- width: non e; m ax-h ei ght: non e; m in- widt h: 0px; m in- hei ght: 0px; paddi ng-to p: 1px; paddin g-b ottom : 1px; pos ition : rela tive; ">b2+c2‐a22bcb2+c2‐a 22bc ; y = a 2&a mp;#x2010;&a mp;#xFD3E;b &a mp;#x2010;c﴿2&a mp;#xFD3E;b+c ﴿2 &a mp;#x2010;a2 " role="p resenta tion " style=" display: in li ne -block; line-height: 0; font- size: 16.38px; word-wra p: no rmal; wo rd-s pa cin g: nor mal; whit e-s pace: no wr ap; fl oat : n one; dire ct ion: l tr; ma x- width: non e; ma x-he ight: non e; m in- widt h: 0px; m in- hei ght: 0px; paddi ng-to p: 1px; paddin g-b ottom: 1px; posi tion: re lat ive; ">a2‐﴾b‐c﴿2﴾b +c﴿2‐a 2a 2‐﴾b‐c﴿2 ﴾b +c ﴿2‐a2. Tính giá trị P = x + y + xyBài 2: Giải phương tr ình:a , 1a+b−x" role="p resenta tion " style=" dis play: i nline -block; line-height: 0; font- si ze: 16.38px; wo rd- wr ap: no rmal; wo rd- spaci ng: normal; white -space: no wr ap; fl oat : no ne; dire ct ion: l tr; ma x- width: non e; m ax-h ei ght: non e; m in- wid th: 0px; min- hei ght: 0px; pa ddi ng-to p: 1px; paddin g-b ottom: 1px; posi tion: rela tive; ">1a+b −x1a +b−x = 1a " role =" prese nta tion " style=" dis play: i nline -block; line-height: 0; font- si ze: 16.38px; wor d-wrap: normal; wo rd-s pa cin g: normal; white-s pace : nowr ap; f lo at : none; dire ct ion: l tr; ma x- width: non e; ma x- heig ht: none; min- widt h: 0p x; min-height: 0px; paddin g- top: 1px; pa ddi ng-botto m: 1px; posit ion: r elati ve; ">1a1a+1b" ro le="pres entat ion " st yle="di spl ay: inli ne-b lock; li ne-he ight: 0; font- si ze: 16.38px; wo rd- wra p: nor ma l; wo rd- spa ci ng: no rma l; white- space: no wr ap; floa t: n one; dire ct ion: ltr; m ax- wid th: non e; ma x-height : none ; min- wi dth: 0p x; min-height: 0px; paddin g-to p: 1px; pa ddin g- bottom: 1px; pos it ion: r elati ve; ">1b1b+ 1x" role ="pres enta tion" style=" display: in li ne -block; line-height: 0; font- si ze: 16.38px; wor d-wrap: no rmal; wo rd-s pa cin g: nor mal; whit e-s pace: no wr ap; fl oat : non e; dire ct ion: l tr; ma x- width: non e; m ax-h ei ght: non e; min- wi dth: 0px; mi n-he ight: 0px; pa ddi ng-to p: 1px; paddin g-b ottom: 1px; posi tion: rela tive;">1x1x ﴾x là ẩn số﴿b, &a mp;#xFD3E; b&am p;#x2010;c&a mp;#xFD3F;&a mp;#xFD3E;1+a &a mp;#xFD3F; 2x+a2" role =" pres enta tion " style=" display: in li ne -block; line-height: 0; font- si ze: 16.38px; wo rd-wra p: n or mal; wo rd- spacin g: nor ma l; white-s pa ce: no wra p; float: non e; di recti on: lt r; ma x- width: no ne; m ax- heig ht: none; min- widt h: 0p x; min-height: 0px; paddin g-to p: 1px; pa ddin g- bottom: 1px; pos it ion: r elati ve; ">﴾b‐c﴿﴾1+a ﴿2x+a 2﴾b‐c﴿﴾1+a﴿2x+a2 + &a mp;#xFD3E; c&a mp;#x2212;a &a mp;#xFD3F;&a mp;#xFD3E; 1+b&am p;#xFD3F;2x+b2" role ="p resenta tion " style=" dis play: i nline -block; line-height: 0; font- si ze: 16.38px; wor d-wra p: no rmal; wo rd-s pacin g: norma l; white-s pa ce: no wra p; float: non e; di rection : lt r; ma x- width: none; m ax- he ight : n one; min- wi dt h: 0p x; min-height: 0px; paddin g-to p: 1px; pa ddin g- bottom: 1px; pos it ion: r elati ve; ">﴾c−a ﴿﴾1+b﴿2x+b2﴾c−a ﴿﴾1+b﴿2x+b2 + &a mp;#xFD3E;a &a mp;#x2212;b&a mp;#xFD3F;&a mp;#xFD3E; 1+c&am p;#xFD3F;2x+c2" role =" pres enta tion " style=" dis play: inli ne -block; line-height: 0; font- si ze: 16.38px; wo rd-wra p: n or mal; wo rd-s pacin g: nor mal ; whi te-s pa ce: no wra p; float: non e; di rectio n: lt r; ma x- width: no ne; ma x-heig ht: none; m in- wid th: 0px; min-h ei ght : 0px ; p adding -t op: 1 px ; pa dding-b ottom: 1 px ; position : relat ive ;">﴾a −b﴿﴾1+ c﴿2x+ c2﴾a −b﴿﴾1+c﴿2x+c2 = 0 ﴾a,b,c là hằng số và đôi một khác nhau﴿
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sửa đổi
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phương trinh toán 8 siêu khó
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phương trinh toán 8 siêu khó Bài 1:
Cho x = \ ﴾\frac{b^2+c^2‐a^2}{2bc} \﴿ ; y = \ ﴾\frac{a^2‐\left﴾b‐c\right﴿^2}{\left﴾b+c\right﴿^2‐a^2} \﴿
Tính giá trị P = x + y + xy Bài 2:
Giải phương trình:
a, \ ﴾\frac{1}{a+b ‐x} \﴿ = \﴾\frac{1}{a} \﴿+ \﴾\frac{1}{b} \﴿+ \﴾\frac{1}{x} \﴿ ﴾x là ẩn số﴿ b, \﴾\frac{\left﴾b‐c\right﴿\left﴾1+a\right﴿^2}{x+a^2} \﴿ + \﴾\frac{\left﴾c‐a\right﴿\left﴾1+b\right﴿^2}{x+b^2} \﴿ + \﴾\frac{\left﴾a‐b\right﴿\left﴾1+c\right﴿^2}
{x+c^2} \﴿ = 0
﴾a,b,c là hằng số và đôi một khác nhau﴿
phương trinh toán 8 siêu khó Bài 1:Cho x = \frac{ b^2+c^2‐a^2}{2bc} ; y = \frac{a^2‐\left﴾b‐c\right﴿^2}{\left﴾b+c\right﴿^2‐a^2} Tính giá trị P = x + y + xy Bài 2:
Giải phương trình:
a, \frac{1}{a+b-x} = \frac{1}{a}+\frac{1}{b}+\frac{1}{x} ﴾x là ẩn số﴿ b, \frac{\left﴾b‐c\right﴿\left﴾1+a\right﴿^2}{x+a^2}+\frac{\left﴾c‐a\right﴿\left﴾1+b\right﴿^2}{x+b^2}+\frac{\left﴾a‐b\right﴿\left﴾1+c\right﴿^2}{x+c^2} = 0
﴾a,b,c là hằng số và đôi một khác nhau﴿
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đặt câu hỏi
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phương trinh toán 8 siêu khó
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$Bài 1:x=\frac{a^2-b^2-c^2}{2bc};y=\frac{a^2-(b-c)^2}{(b+c)^2-a^2}.Tính: x+y+xy$ Bài 2:Giải phương trình: $a,\frac{1}{a+b-x}=\frac{1}{a}+\frac{1}{b}+\frac{1}{x}$ $c,\Sigma\frac{(b-c)(1+a^2)}{x+a^2}=0$
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