Tính $I = \int\limits_{\frac{\pi }{6}}^{\frac{\pi }{3}} {\sqrt {\tan^2x + \cot ^2x - 2} \,dx} $
Trả lời 09-07-12 12:28 AM
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$\int\limits_{0}^{\frac{\pi}{2}} \cos ( 40x + \frac{\pi}{2} )dx$$ \int\limits_{0}^{\pi} 3\sin (33x + 3)dx $
Trả lời 01-12-12 03:43 PM
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$ \int\limits_{0}^{\pi/4} xtg^{2}xdx{}$$ \int\limits_{0}^{\pi/2}\frac{3sinx + 4cosx}{4cos^{2}x + 3sin^{2}x} dx$
Trả lời 07-12-12 10:54 PM
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$\int\limits_{0}^{pi/2}\frac{\sqrt{sinx}}{\sqrt{sinx}+\sqrt{cosx}}dx$
Trả lời 01-02-13 04:45 PM
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Trả lời 23-03-16 08:07 PM
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$$\int\limits_{\frac{pi}{3}}^{pi} \frac{1}{2+\sqrt{3}\sin x-\cos x}dx$$
Trả lời 03-07-16 04:29 PM
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Trả lời 23-03-16 08:07 PM
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$ \int\limits_{0}^{\pi/4}\dfrac{1 +\sin2x}{\cos^{2}x}dx $$ \int\limits_{0}^{\pi/2}\dfrac{\cos^{3}x}{1 + \cos x}dx $
Trả lời 07-12-12 10:45 PM
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$\int\limits_{0}^{\frac{\Pi }{2}}\frac{1+\sin x}{1+\cos x}e^{x}dx$
Trả lời 17-05-13 08:59 PM
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$ \int\limits_{0}^{\pi/2} \frac{\sin^{3}x dx}{2 + \cos x}$$ \int\limits_{0}^{\pi/2} \frac{dx}{\sin x + \cos x +3}$
Trả lời 07-12-12 11:20 PM
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$\int\limits_{0}^{\frac{\pi}{2}} \cos ( 40x + \frac{\pi}{2} )dx$$ \int\limits_{0}^{\pi} 3\sin (33x + 3)dx $
Trả lời 01-12-12 03:44 PM
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$\int\limits_{0}^{\frac{\pi}{2}} \cos ( 40x + \frac{\pi}{2} )dx$$ \int\limits_{0}^{\pi} 3\sin (33x + 3)dx $
Trả lời 01-12-12 03:44 PM
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$ \int\limits_{\pi/6}^{\pi/3}\frac{dx}{\sin x.\sin(x +\pi/6)}$$ \int\limits_{0}^{\pi/2}\frac{4\sin x}{(\cos x + \sin x)^{3}} dx$
Trả lời 07-12-12 11:38 PM
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$ \int\limits_{}^{} \frac{dx}{cosx.cos(x +a )} $$ \int\limits_{}^{} tan(x + \pi/3).cotg(x-\pi/6)dx $
Trả lời 07-12-12 11:48 PM
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$ \int\limits_{}^{} \frac{dx}{cosx.cos(x +a )} $$ \int\limits_{}^{} tan(x + \pi/3).cotg(x-\pi/6)dx $
Trả lời 07-12-12 11:56 PM
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