1.CM $\mathop {\lim }\limits_{n \to +\infty }\int\limits_{0}^{1}x^{n}.sin\pi x dx=0$
Trả lời 02-07-17 04:31 AM
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$\mathop {\lim }\limits_{x \to 0}\frac{tanx-sinx}{x.tanx.sinx}$
Trả lời 20-04-17 01:09 AM
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tính $\mathop {\lim }\limits_{x \to +\infty }\frac{\sqrt{x^{4}+x+1}-\sqrt{x^{4}+7}}{x^{3}-1}$
Trả lời 08-03-17 07:39 PM
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tính $\mathop {\lim }\limits_{x \to +\infty }(x-2017)\sqrt{\frac{2x+3}{x^{3}-4}}$
Trả lời 08-03-17 07:37 PM
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$\mathop {\lim }\limits_{x \to 1}\frac{\sqrt{x}.\sqrt[3]{x}.\sqrt[4]{x}...\sqrt[2017]{x}-1}{x-1}$
Trả lời 21-02-17 06:13 AM
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$I_{1}=\mathop {\lim }\limits_{x \to +\infty }\frac{1^{3}+5^{3}+...+(4x-3)^{3}}{(1+5+...+4x-3)^{2}}$$I_{2}=\mathop {\lim }\limits_{x \to +\infty }\frac{\sin \pi x+4\sqrt[3]{x}}{\sqrt[3]{x}}$
Trả lời 20-02-17 07:54 AM
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$I_{1}=\mathop {\lim }\limits_{x \to +\infty }\frac{1^{3}+5^{3}+...+(4x-3)^{3}}{(1+5+...+4x-3)^{2}}$$I_{2}=\mathop {\lim }\limits_{x \to +\infty }\frac{\sin \pi x+4\sqrt[3]{x}}{\sqrt[3]{x}}$
Trả lời 20-02-17 07:46 AM
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$ \mathop {\lim }\limits_{x \to 1}\frac{2-\sqrt{2x-1}\sqrt[3]{5x+3}}{x-1} $
Trả lời 19-02-17 04:02 AM
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tính $\mathop {\lim }\limits_{n \to +\infty }\frac{2+4+...+2^{n}}{2^{n+1}-3}$
Trả lời 19-02-17 03:44 AM
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tính $\mathop {\lim }\limits_{n \to +\infty }\frac{1+4+7+...+(3n-2)}{3n^{2}-4}$
Trả lời 19-02-17 03:41 AM
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tính $\mathop {\lim }\limits_{x \to 3}\frac{x^{3}-2\left| {x+3} \right|+3\left| {x-4} \right|-18}{2x^{2}-3x-9}$
Trả lời 19-02-17 03:37 AM
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$\mathop {\lim }\limits_{x \to +\infty }( \sqrt{(x+\sqrt{x+\sqrt{x}}}- \sqrt{x})$mọi người giải giùm mk ạ
Trả lời 11-02-17 08:14 PM
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chứng minh $\mathop {\lim }\limits_{x \to +\infty } cos x$ không tồn tại?
Trả lời 03-02-17 07:07 AM
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tính $\mathop {\lim }\limits_{x \to 0}\frac{\left| {1-\left| {1+sin3x} \right|} \right|}{\sqrt{1-cosx}}$
Trả lời 25-01-17 08:07 AM
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Bài toán :
Trả lời 24-01-17 07:03 PM
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$\mathop {\lim }\limits_{x \to 0}\frac{(1-\cos x)^2}{\tan^3 x-\sin^3 x}$
Trả lời 24-01-17 06:31 PM
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tính $\mathop {\lim }\limits_{x \to 1}\frac{(x+1)\sqrt{x+3}-(2x-1)\sqrt{9x+7}}{x-1}$
Trả lời 24-01-17 03:29 PM
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$\mathop {\lim }\limits_{x \to 0}\frac{sinx.cosx-sinx}{sin\frac{x}{2}}$
Trả lời 24-01-17 02:49 PM
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tính $\mathop {\lim }\limits_{x \to 0}\frac{sinx}{tan2x}$
Trả lời 24-01-17 02:29 PM
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tính $\mathop {\lim }\limits_{x \to 0}\frac{sin5x.sin3x.sinx}{45x^{3}}$
Trả lời 24-01-17 02:21 PM
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