DK:.....+) x=−1 k là no of pt
+)
x≠−1pt
⇔x+4=(√x+2+1)(1+4(3√2x+3−1)2x+3−1) ⇔(x+4)(x+1)=(√x+2+1)(23√2x+3+x−1)
⇔(x+4)(√x+2+1)(√x+2−1)=(√x+2+1)(23√2x+3+x−1)
⇔(x+4)√x+2−x−4=23√2x+3+x−1
⇔(√x+2)3+2√x+2=2x+3+23√2x+3
⇔(√x+2−3√2x+3)(....)=0
⇔√x+2=3√2x+3
Đến đây bạn giải tip nhé!!! :D