Ngoài ra dùng PytagoĐặt $HB=x;AC=y$
Pytago: $AB^2-HB^2=AC^2-HC^2=AH^2\Rightarrow 16-x^2=y^2-36\Rightarrow y^2=52-x^2$(*)
$AB^2+AC^2=BC^2\Rightarrow 16+y^2=(x+6)^2$ Thay (*) vào ta có:
$\Rightarrow 16+52-x^2=x^2+12x+36\Rightarrow 2x^2+12x-32=0\Rightarrow 2.(x-2)(x+8)=0$
$\Rightarrow x=2;x=-8(loại)$
Vậy $BC=6+x=8cm$