Phương trình đã cho tương đương với:
$2^{2x^2-2x+1}-9.2^{x^2-x}+2^2=0$
$\Leftrightarrow 2.2^{2(x^2-x)}-9.2^{x^2-x}+4=0$
$\Leftrightarrow \left[\begin{array}{l}2^{x^2-x}=4\\2^{x^2-x}=\dfrac{1}{2}\end{array}\right.$
$\Leftrightarrow \left[\begin{array}{l}x^2-x=2\\x^2-x=-1\end{array}\right.$
$\Leftrightarrow \left[\begin{array}{l}x=2\\x=-1\end{array}\right.$