$\Leftrightarrow 2^{\frac{2(x-1)}{x+1}} \le2^{-2} . 2^{\frac{5x}{x-2}} = 2^{\frac{5x}{x-2}-2} = 2^{\frac{3x+4}{x-2}}$
$\Leftrightarrow \dfrac{2(x-1)}{x+1} \le \dfrac{3x+4}{x-2}$
lập bảng xét dấu ra là ok
$KQ = \left [ \begin{matrix} x >2 \\ -1 <x \le 0 \\ x \le -13 \end{matrix} \right.$