tim gia tri nho nhat cua bieu thuc
Cho a,b,c la 3 so thuc duong thoa man $abc=1$. Tim gia tri nho nhat cua bieu thuc
$S = $\frac{a^{2}}{(ab+2)(2ab+1)}$ + $\frac{b^{2}}{(bc+2)(2bc+1)}$ + $\frac{c^{2}}{(ac+2)(2ac+1)}$
tim gia tri nho nhat cua bieu thuc
Cho a,b,c la 3 so thuc duong thoa man $abc=1$. Tim gia tri nho nhat cua bieu thucS = $\frac{a^{2}}{(ab+2)(2ab+1)}$ + $\frac{b^{2}}{(bc+2)(2bc+1)}$ + $\frac{c^{2}}{(ac+2)(2ac+1)}$