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bình luận
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Bài 108958
a) BPT ⇔x 2−3x 3>3x 9⇔5x<−4⇔x<−45⇔x 2−3x 3>3x 9⇔5x<−4⇔x<−4/5Vậy S=(−∞;−45)S=(−∞;−4/5)b)BPT ⇔9x 15−6≤2x 4 6x⇔x≤−5⇔9x 15−6≤2x 4 6x⇔x≤−5Vậy S=(−∞;−5]S=(−∞;−5]c) Vì 1−2–√<01−2<0 nên BPT tương đương(1−2–√)x<(1−2–√)2⇔x>1−2–√(1−2)x<(1−2)2⇔x>1−2Vậy S=(1−2–√; ∞)S
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