\log2x (x2 - 5x +6) < 1DK:x \neq 1/2 va x2 - 5x +6 > 0 <=> x(- \infty ,2 ) va x(3,+ \infty )pt: \log2x (x2 - 5x + 6)< \log2x 2x<=> x2 -5x + 6 < 2x <=> x2 - 7x + 6 <0 <=> x(1,6)so dk x(1,2) va x(3,6)
\log2x (x2 - 5x +6) < 1DK:x \neq 1/2 va x2 - 5x +6 > 0 <=> x(- \infty ,2 ) va x(3,+ \infty )pt: log2x (x2 - 5x + 6)< log2x 2x<=> x2 -5x + 6 < 2x <=> x2 - 7x + 6 <0 <=> x(1,6)so dk x(1,2) va x(3,6)