to giai tom tat nha khong nhap dk cong thuc tach thanh 2 tich phantich phan thu nhat nhan can(1-canx) ca tu va mau roi dat x=(sinx)^2 cau tu lam tieptich phan thu 2 lam tung phan binh thuong chu y v=dx thi nen de v=x+1 u=ln(x+1) thi du=1/(x+1) de nhanh hon
to giai tom tat nha khong nhap dk cong thuc tach thanh 2 tich phantich phan thu nhat nhan can(1-canx) ca tu va mau roi dat x=(sinx)^2 cau tu lam tieptich phan thu 2 lam tung phan binh thuong chu y v=dx thi nen de v=x+1 u=ln(x+1) thi du=1/(x+1) de nhanh honlam tiep cho ban de hieu hon nha sau khi cai thu nhat ay se thanh (1-canx)/can(1-x) dat x=(sint)^2 voi t thuoc [0;pi/2] doi can...khi do se dk (1-sint)/cost=1/cost-sint/cost hai cai nay qua de roi