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được thưởng
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Đăng nhập hàng ngày 02/06/2013
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đặt câu hỏi
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bai nay kho the
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cho (E) :$\frac{x^{2}}{8}+\frac{y^{2}}{2}$=1vadiem A(4;5). tim diem M tren (E) sao cho khoang cach MA min
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đặt câu hỏi
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bai nay kho the
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cho E:$\frac{x^{2}}{8}+\frac{y^{2}}{2}$=1va duong thang d:3x+4y+24=0
tim M tren E sao cho khoang kach tu M den d min
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đặt câu hỏi
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bai nay thi trau do
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cho d1:x-y-2=0 cat d2:x+2y-2=0tai I viet phuong trinh$ \Delta $ quaM(-1;1) cat d1,d2 lan luot la A, Bsao cho AB=3IA
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đặt câu hỏi
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to hop kho
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co 12 chiec banh ngot khac nhau hoi co bao nhieu cach xep chung vao 6 hop giong nhau sao cho moi hop co 2 chiec banh
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sửa đổi
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BĐT hay va kho
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x3+y3=(x+y)3-3xy(x+y)$\geqslant(x+y)^{3}-\frac{3}{4}(x+y)^{3}$=$\frac{(x+y)^{3}}{4}$
4(x3+y3)$\geqslant $(x+y)3 tuong tu
4(y3+z3)$\geqslant $(y+x)3 ;4(x3+z3)$\geqslant $(x+z)3
$\sqrt[3]{4(x^{3}+y^{3})}$+$\sqrt[3]{4(x^{3}+z^{3})}$+$\sqrt[3]{4(y^{3}+z^{3})}$$\geqslant $6$\sqrt[3]{xyz}$$2(\frac{x}{y^{2}}+\frac{y}{z^{2}}+\frac{z}{x^{2}})\geqslant \frac{6}{\sqrt[3]{xyz}}$$P\geqslant 6(\sqrt[3]{xyz}+\frac{1}{\sqrt[3]{xyz}})\geqslant 12$
Pmin =12 khi x=y=z=1
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