Đk : x > 12 Ta có VT = x + (2-1x) +y + (2-1y)<=> VT= x+ 2x−1x + y + 2y−1y<=>VT\geq2\sqrt{2x-1}+2\sqrt{2y-1}Dấu=xảyra<=>x^{2}=2x−1y^{2}$=2y-1 <=> x=y=1 (TM)
Đk : x > 12 Ta có VT = x + (2-1x) +y + (2-1y)<=> VT= x+ 2x−1x + y + $\frac{2y-1}{y}$<=> VT ≥ 2√2x−1 + 2√2y−1Dấu = xảy ra <=> x2=2x-1 y2=2y-1 <=> x=y=1 (TM)