\displaystyle{\left\{ \begin{array}{l}\sqrt{x-1}-x+3y-2\sqrt[3]{3y+2}=1\\ x+\sqrt{x-1}-3y-2\sqrt[3]{3y+2} =-7\end{array} \right}.
\Leftrightarrow \left\{ 2x−6y=−82√x−1−43√3y+2=−6 \right.
\Leftrightarrow \left\{ x=3y−4(1)√x−1=3√3y+2−3(2) \right.
thay (1) vao` (2) ta co': \sqrt{3y-5}=\sqrt[3]{3y+2}-3
Dat. t=\sqrt[3]{3y+2} giai tim` t\rightarrowy\rightarrowx