1) log√278=2log32=b⇒log32=b2⇒log23=2b$\log_{25} 45 = \dfrac{3}{2}\log_5 3 + \dfrac{1}{2} = \dfrac{1}{2} + \dfrac{3}{2} \dfrac{\log_2 3}{\log_2 5}KQ= \dfrac{1}{2} + \dfrac{3}{2}. \dfrac{2}{ab} = \dfrac{3}{ab} $
1)
log√278=2log32=b⇒log32=b2⇒log23=2blog2545=log53+12=12+log23log25KQ
=12+2ab