1) $\log_{\sqrt{27}} 8 = 2\log_3 2 = b \Rightarrow \log_3 2 = \dfrac{b}{2} \Rightarrow \log_2 3 = \dfrac{2}{b}$$\log_{25} 45 = \log_5 3 + \dfrac{1}{2} = \dfrac{1}{2} + \dfrac{\log_2 3}{\log_2 5}$KQ $= \dfrac{1}{2} + \dfrac{2}{ab} $
1) $\log_{\sqrt{27}} 8 = 2\log_3 2 = b \Rightarrow \log_3 2 = \dfrac{b}{2} \Rightarrow \log_2 3 = \dfrac{2}{b}$$\log_{25} 45 = \dfrac{3}{2}\log_5 3 + \dfrac{1}{2} = \dfrac{1}{2} + \dfrac{3}{2} \dfrac{\log_2 3}{\log_2 5}$KQ $= \dfrac{1}{2} + \dfrac{3}{2}. \dfrac{2}{ab} = \dfrac{3}{ab} $
1) $\log_{\sqrt{27}} 8 = 2\log_3 2 = b \Rightarrow \log_3 2 = \dfrac{b}{2} \Rightarrow \log_2 3 = \dfrac{2}{b}$$\log_{25} 45 = \log_5 3 + \dfrac{1}{2} = \dfrac{1}{2} + \dfrac{\log_2 3}{\log_2 5}$KQ $= \dfrac{1}{2} + \dfrac{2}{ab} $