lay hai lan pt duoi tru mot lan pt tren ta co$x^2+2-3y+2\sqrt{y(x^2+2)}=0\Leftrightarrow 1-\frac{3y}{x^2+2}+2\sqrt{\frac{y}{x^2+2}}=0$$=>y=x^2+2$ thay vao pt doi ta co$x^3+x^2+3x+3=0 =>x=-1=>y=3$
lay hai lan pt duoi tru mot lan pt tren ta co$x^2+2-3y+2\sqrt{y(x^2+2)}=0\Leftrightarrow 1-\frac{3y}{x^2+2}+2\sqrt{\frac{y}{x^2+2}}=0$$=>y=x^2+2$ thay vao pt doi ta co$x^3+x^2+2x+3=0 =>x=........$ (minh ko co may tinh .tu lam nha)
lay hai lan pt duoi tru mot lan pt tren ta co$x^2+2-3y+2\sqrt{y(x^2+2)}=0\Leftrightarrow 1-\frac{3y}{x^2+2}+2\sqrt{\frac{y}{x^2+2}}=0$$=>y=x^2+2$ thay vao pt doi ta co$x^3+x^2+
3x+3=0 =>x=
-1=>y=3$