$\left\{\begin{matrix} 3(x+\frac{1}{x})=4(y+\frac{1}{y})=5(z+\frac{1}{z}) & \\ &xy+yz+xz=1 \end{matrix}\right.$
$\left\{\begin{matrix} 3(x+\frac{1}{x})=4(y+\frac{1}{y})=5(z+\frac{1}{z}) \\ xy+yz+xz=1 \end{matrix}\right.$
Hệ phương trình
$\left\{\begin{matrix} 3(x+\frac{1}{x})=4(y+\frac{1}{y})=5(z+\frac{1}{z}) & \\ &xy+yz+xz=1 \end{matrix}\right.$
$\left\{\begin{matrix} 3(x+\frac{1}{x})=4(y+\frac{1}{y})=5(z+\frac{1}{z})
& \\
&xy+yz+xz=1 \end{matrix}\right.$
Hệ phương trình
$\left\{\begin{matrix} 3(x+\frac{1}{x})=4(y+\frac{1}{y})=5(z+\frac{1}{z}) & \\ &xy+yz+xz=1 \end{matrix}\right.$
$\left\{\begin{matrix} 3(x+\frac{1}{x})=4(y+\frac{1}{y})=5(z+\frac{1}{z}) \\ xy+yz+xz=1 \end{matrix}\right.$
Hệ phương trình